Elijah had a total of 172 apples and lemons. He sold
34 of the lemons and bought another 8 apples. In the end, the number of apples he had was
12 the number of lemons. How many more lemons than apples did he have at first?
| |
Apples |
Lemons |
Total |
Before
|
1 u - 8
|
4x2 =
8 u |
172 |
Change |
+ 8 |
- 3x2 =
6 u |
|
| After |
|
1x2 =
2 u |
|
Comparing between
apples and lemons |
1x1 =
1 u |
2x1 =
2 u |
|
The number of lemons in the end is repeated. Make the number of lemons in the end the same. LCM of 1 and 2 is 2.
Total number of apples and lemons at first
= 1 u - 8 + 8 u
= 9 u - 8
9 u - 8 = 172
9 u = 172 + 8
9 u = 180
1 u = 180 ÷ 9 = 20
Number of more lemons than apples at first
= 8 u - (1 u - 8)
= 8 u - 1 u + 8
= 7 u + 8
= 7 x 20 + 8
= 140 + 8
= 148
Answer(s): 148
