Riordan had a total of 264 chikoos and mangosteens. He sold
14 of the mangosteens and bought another 40 chikoos. In the end, the number of chikoos he had was
14 the number of mangosteens. How many more mangosteens than chikoos did he have at first?
| |
Chikoos |
Mangosteens |
Total |
Before
|
3 u - 40
|
4x4 =
16 u |
264 |
Change |
+ 40 |
- 1x4 =
4 u |
|
| After |
|
3x4 =
12 u |
|
Comparing between
chikoos and mangosteens |
1x3 =
3 u |
4x3 =
12 u |
|
The number of mangosteens in the end is repeated. Make the number of mangosteens in the end the same. LCM of 3 and 4 is 12.
Total number of chikoos and mangosteens at first
= 3 u - 40 + 16 u
= 19 u - 40
19 u - 40 = 264
19 u = 264 + 40
19 u = 304
1 u = 304 ÷ 19 = 16
Number of more mangosteens than chikoos at first
= 16 u - (3 u - 40)
= 16 u - 3 u + 40
= 13 u + 40
= 13 x 16 + 40
= 208 + 40
= 248
Answer(s): 248
