Howard had a total of 219 apples and pomegranates. He sold
34 of the pomegranates and bought another 33 apples. In the end, the number of apples he had was
12 the number of pomegranates. How many more pomegranates than apples did he have at first?
| |
Apples |
Pomegranates |
Total |
Before
|
1 u - 33
|
4x2 =
8 u |
219 |
Change |
+ 33 |
- 3x2 =
6 u |
|
| After |
|
1x2 =
2 u |
|
Comparing between
apples and pomegranates |
1x1 =
1 u |
2x1 =
2 u |
|
The number of pomegranates in the end is repeated. Make the number of pomegranates in the end the same. LCM of 1 and 2 is 2.
Total number of apples and pomegranates at first
= 1 u - 33 + 8 u
= 9 u - 33
9 u - 33 = 219
9 u = 219 + 33
9 u = 252
1 u = 252 ÷ 9 = 28
Number of more pomegranates than apples at first
= 8 u - (1 u - 33)
= 8 u - 1 u + 33
= 7 u + 33
= 7 x 28 + 33
= 196 + 33
= 229
Answer(s): 229
