Billy had a total of 278 pomegranates and persimmons. He sold
15 of the persimmons and bought another 26 pomegranates. In the end, the number of pomegranates he had was
13 the number of persimmons. How many more persimmons than pomegranates did he have at first?
| |
Pomegranates |
Persimmons |
Total |
Before
|
4 u - 26
|
5x3 =
15 u |
278 |
Change |
+ 26 |
- 1x3 =
3 u |
|
| After |
|
4x3 =
12 u |
|
Comparing between
pomegranates and persimmons |
1x4 =
4 u |
3x4 =
12 u |
|
The number of persimmons in the end is repeated. Make the number of persimmons in the end the same. LCM of 4 and 3 is 12.
Total number of pomegranates and persimmons at first
= 4 u - 26 + 15 u
= 19 u - 26
19 u - 26 = 278
19 u = 278 + 26
19 u = 304
1 u = 304 ÷ 19 = 16
Number of more persimmons than pomegranates at first
= 15 u - (4 u - 26)
= 15 u - 4 u + 26
= 11 u + 26
= 11 x 16 + 26
= 176 + 26
= 202
Answer(s): 202
