Asher had a total of 507 kiwis and oranges. He sold
25 of the oranges and bought another 37 kiwis. In the end, the number of kiwis he had was
35 the number of oranges. How many more oranges than kiwis did he have at first?
| |
Kiwis |
Oranges |
Total |
Before
|
9 u - 37
|
5x5 =
25 u |
507 |
Change |
+ 37 |
- 2x5 =
10 u |
|
| After |
|
3x5 =
15 u |
|
Comparing between
kiwis and oranges |
3x3 =
9 u |
5x3 =
15 u |
|
The number of oranges in the end is repeated. Make the number of oranges in the end the same. LCM of 3 and 5 is 15.
Total number of kiwis and oranges at first
= 9 u - 37 + 25 u
= 34 u - 37
34 u - 37 = 507
34 u = 507 + 37
34 u = 544
1 u = 544 ÷ 34 = 16
Number of more oranges than kiwis at first
= 25 u - (9 u - 37)
= 25 u - 9 u + 37
= 16 u + 37
= 16 x 16 + 37
= 256 + 37
= 293
Answer(s): 293
