Dylan had a total of 222 apples and chikoos. He sold
34 of the chikoos and bought another 38 apples. In the end, the number of apples he had was
13 the number of chikoos. How many more chikoos than apples did he have at first?
| |
Apples |
Chikoos |
Total |
Before
|
1 u - 38
|
4x3 =
12 u |
222 |
Change |
+ 38 |
- 3x3 =
9 u |
|
| After |
|
1x3 =
3 u |
|
Comparing between
apples and chikoos |
1x1 =
1 u |
3x1 =
3 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 1 and 3 is 3.
Total number of apples and chikoos at first
= 1 u - 38 + 12 u
= 13 u - 38
13 u - 38 = 222
13 u = 222 + 38
13 u = 260
1 u = 260 ÷ 13 = 20
Number of more chikoos than apples at first
= 12 u - (1 u - 38)
= 12 u - 1 u + 38
= 11 u + 38
= 11 x 20 + 38
= 220 + 38
= 258
Answer(s): 258
