Ian had a total of 356 apples and lemons. He sold
13 of the lemons and bought another 35 apples. In the end, the number of apples he had was
45 the number of lemons. How many more lemons than apples did he have at first?
| |
Apples |
Lemons |
Total |
Before
|
8 u - 35
|
3x5 =
15 u |
356 |
Change |
+ 35 |
- 1x5 =
5 u |
|
| After |
|
2x5 =
10 u |
|
Comparing between
apples and lemons |
4x2 =
8 u |
5x2 =
10 u |
|
The number of lemons in the end is repeated. Make the number of lemons in the end the same. LCM of 2 and 5 is 10.
Total number of apples and lemons at first
= 8 u - 35 + 15 u
= 23 u - 35
23 u - 35 = 356
23 u = 356 + 35
23 u = 391
1 u = 391 ÷ 23 = 17
Number of more lemons than apples at first
= 15 u - (8 u - 35)
= 15 u - 8 u + 35
= 7 u + 35
= 7 x 17 + 35
= 119 + 35
= 154
Answer(s): 154
