Nick had a total of 517 kiwis and apples. He sold
34 of the apples and bought another 29 kiwis. In the end, the number of kiwis he had was
15 the number of apples. How many more apples than kiwis did he have at first?
| |
Kiwis |
Apples |
Total |
Before
|
1 u - 29
|
4x5 =
20 u |
517 |
Change |
+ 29 |
- 3x5 =
15 u |
|
| After |
|
1x5 =
5 u |
|
Comparing between
kiwis and apples |
1x1 =
1 u |
5x1 =
5 u |
|
The number of apples in the end is repeated. Make the number of apples in the end the same. LCM of 1 and 5 is 5.
Total number of kiwis and apples at first
= 1 u - 29 + 20 u
= 21 u - 29
21 u - 29 = 517
21 u = 517 + 29
21 u = 546
1 u = 546 ÷ 21 = 26
Number of more apples than kiwis at first
= 20 u - (1 u - 29)
= 20 u - 1 u + 29
= 19 u + 29
= 19 x 26 + 29
= 494 + 29
= 523
Answer(s): 523
