Jenson had a total of 244 starfruits and chikoos. He sold
12 of the chikoos and bought another 9 starfruits. In the end, the number of starfruits he had was
15 the number of chikoos. How many more chikoos than starfruits did he have at first?
| |
Starfruits |
Chikoos |
Total |
Before
|
1 u - 9
|
2x5 =
10 u |
244 |
Change |
+ 9 |
- 1x5 =
5 u |
|
| After |
|
1x5 =
5 u |
|
Comparing between
starfruits and chikoos |
1x1 =
1 u |
5x1 =
5 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 1 and 5 is 5.
Total number of starfruits and chikoos at first
= 1 u - 9 + 10 u
= 11 u - 9
11 u - 9 = 244
11 u = 244 + 9
11 u = 253
1 u = 253 ÷ 11 = 23
Number of more chikoos than starfruits at first
= 10 u - (1 u - 9)
= 10 u - 1 u + 9
= 9 u + 9
= 9 x 23 + 9
= 207 + 9
= 216
Answer(s): 216
