Jenson had a total of 700 chikoos and lemons. He sold
25 of the lemons and bought another 40 chikoos. In the end, the number of chikoos he had was
45 the number of lemons. How many more lemons than chikoos did he have at first?
| |
Chikoos |
Lemons |
Total |
Before
|
12 u - 40
|
5x5 =
25 u |
700 |
Change |
+ 40 |
- 2x5 =
10 u |
|
| After |
|
3x5 =
15 u |
|
Comparing between
chikoos and lemons |
4x3 =
12 u |
5x3 =
15 u |
|
The number of lemons in the end is repeated. Make the number of lemons in the end the same. LCM of 3 and 5 is 15.
Total number of chikoos and lemons at first
= 12 u - 40 + 25 u
= 37 u - 40
37 u - 40 = 700
37 u = 700 + 40
37 u = 740
1 u = 740 ÷ 37 = 20
Number of more lemons than chikoos at first
= 25 u - (12 u - 40)
= 25 u - 12 u + 40
= 13 u + 40
= 13 x 20 + 40
= 260 + 40
= 300
Answer(s): 300
