Cody had a total of 437 kiwis and pomegranates. He sold
34 of the pomegranates and bought another 38 kiwis. In the end, the number of kiwis he had was
34 the number of pomegranates. How many more pomegranates than kiwis did he have at first?
| |
Kiwis |
Pomegranates |
Total |
Before
|
3 u - 38
|
4x4 =
16 u |
437 |
Change |
+ 38 |
- 3x4 =
12 u |
|
| After |
|
1x4 =
4 u |
|
Comparing between
kiwis and pomegranates |
3x1 =
3 u |
4x1 =
4 u |
|
The number of pomegranates in the end is repeated. Make the number of pomegranates in the end the same. LCM of 1 and 4 is 4.
Total number of kiwis and pomegranates at first
= 3 u - 38 + 16 u
= 19 u - 38
19 u - 38 = 437
19 u = 437 + 38
19 u = 475
1 u = 475 ÷ 19 = 25
Number of more pomegranates than kiwis at first
= 16 u - (3 u - 38)
= 16 u - 3 u + 38
= 13 u + 38
= 13 x 25 + 38
= 325 + 38
= 363
Answer(s): 363
