Gabriel had a total of 1220 pomegranates and apples. He sold
15 of the apples and bought another 10 pomegranates. In the end, the number of pomegranates he had was
45 the number of apples. How many more apples than pomegranates did he have at first?
| |
Pomegranates |
Apples |
Total |
Before
|
16 u - 10
|
5x5 =
25 u |
1220 |
Change |
+ 10 |
- 1x5 =
5 u |
|
| After |
|
4x5 =
20 u |
|
Comparing between
pomegranates and apples |
4x4 =
16 u |
5x4 =
20 u |
|
The number of apples in the end is repeated. Make the number of apples in the end the same. LCM of 4 and 5 is 20.
Total number of pomegranates and apples at first
= 16 u - 10 + 25 u
= 41 u - 10
41 u - 10 = 1220
41 u = 1220 + 10
41 u = 1230
1 u = 1230 ÷ 41 = 30
Number of more apples than pomegranates at first
= 25 u - (16 u - 10)
= 25 u - 16 u + 10
= 9 u + 10
= 9 x 30 + 10
= 270 + 10
= 280
Answer(s): 280
