Eric had a total of 483 starfruits and chikoos. He sold
14 of the chikoos and bought another 37 starfruits. In the end, the number of starfruits he had was
25 the number of chikoos. How many more chikoos than starfruits did he have at first?
| |
Starfruits |
Chikoos |
Total |
Before
|
6 u - 37
|
4x5 =
20 u |
483 |
Change |
+ 37 |
- 1x5 =
5 u |
|
| After |
|
3x5 =
15 u |
|
Comparing between
starfruits and chikoos |
2x3 =
6 u |
5x3 =
15 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 3 and 5 is 15.
Total number of starfruits and chikoos at first
= 6 u - 37 + 20 u
= 26 u - 37
26 u - 37 = 483
26 u = 483 + 37
26 u = 520
1 u = 520 ÷ 26 = 20
Number of more chikoos than starfruits at first
= 20 u - (6 u - 37)
= 20 u - 6 u + 37
= 14 u + 37
= 14 x 20 + 37
= 280 + 37
= 317
Answer(s): 317
