Cole had a total of 377 kiwis and apples. He sold
13 of the apples and bought another 14 kiwis. In the end, the number of kiwis he had was
45 the number of apples. How many more apples than kiwis did he have at first?
| |
Kiwis |
Apples |
Total |
Before
|
8 u - 14
|
3x5 =
15 u |
377 |
Change |
+ 14 |
- 1x5 =
5 u |
|
| After |
|
2x5 =
10 u |
|
Comparing between
kiwis and apples |
4x2 =
8 u |
5x2 =
10 u |
|
The number of apples in the end is repeated. Make the number of apples in the end the same. LCM of 2 and 5 is 10.
Total number of kiwis and apples at first
= 8 u - 14 + 15 u
= 23 u - 14
23 u - 14 = 377
23 u = 377 + 14
23 u = 391
1 u = 391 ÷ 23 = 17
Number of more apples than kiwis at first
= 15 u - (8 u - 14)
= 15 u - 8 u + 14
= 7 u + 14
= 7 x 17 + 14
= 119 + 14
= 133
Answer(s): 133
