Owen had a total of 667 persimmons and lemons. He sold
14 of the lemons and bought another 23 persimmons. In the end, the number of persimmons he had was
15 the number of lemons. How many more lemons than persimmons did he have at first?
|
Persimmons |
Lemons |
Total |
Before
|
3 u - 23
|
4x5 = 20 u |
667 |
Change |
+ 23 |
- 1x5 = 5 u |
|
After |
|
3x5 = 15 u |
|
Comparing between persimmons and lemons |
1x3 = 3 u |
5x3 = 15 u |
|
The number of lemons in the end is repeated. Make the number of lemons in the end the same. LCM of 3 and 5 is 15.
Total number of persimmons and lemons at first
= 3 u - 23 + 20 u
= 23 u - 23
23 u - 23 = 667
23 u = 667 + 23
23 u = 690
1 u = 690 ÷ 23 = 30
Number of more lemons than persimmons at first
= 20 u - (3 u - 23)
= 20 u - 3 u + 23
= 17 u + 23
= 17 x 30 + 23
= 510 + 23
= 533
Answer(s): 533