Howard had a total of 824 starfruits and apples. He sold
25 of the apples and bought another 27 starfruits. In the end, the number of starfruits he had was
45 the number of apples. How many more apples than starfruits did he have at first?
| |
Starfruits |
Apples |
Total |
Before
|
12 u - 27
|
5x5 =
25 u |
824 |
Change |
+ 27 |
- 2x5 =
10 u |
|
| After |
|
3x5 =
15 u |
|
Comparing between
starfruits and apples |
4x3 =
12 u |
5x3 =
15 u |
|
The number of apples in the end is repeated. Make the number of apples in the end the same. LCM of 3 and 5 is 15.
Total number of starfruits and apples at first
= 12 u - 27 + 25 u
= 37 u - 27
37 u - 27 = 824
37 u = 824 + 27
37 u = 851
1 u = 851 ÷ 37 = 23
Number of more apples than starfruits at first
= 25 u - (12 u - 27)
= 25 u - 12 u + 27
= 13 u + 27
= 13 x 23 + 27
= 299 + 27
= 326
Answer(s): 326
