Cole had a total of 139 pomegranates and mangoes. He sold
13 of the mangoes and bought another 23 pomegranates. In the end, the number of pomegranates he had was
34 the number of mangoes. How many more mangoes than pomegranates did he have at first?
| |
Pomegranates |
Mangoes |
Total |
Before
|
3 u - 23
|
3x2 =
6 u |
139 |
Change |
+ 23 |
- 1x2 =
2 u |
|
| After |
|
2x2 =
4 u |
|
Comparing between
pomegranates and mangoes |
3x1 =
3 u |
4x1 =
4 u |
|
The number of mangoes in the end is repeated. Make the number of mangoes in the end the same. LCM of 2 and 4 is 4.
Total number of pomegranates and mangoes at first
= 3 u - 23 + 6 u
= 9 u - 23
9 u - 23 = 139
9 u = 139 + 23
9 u = 162
1 u = 162 ÷ 9 = 18
Number of more mangoes than pomegranates at first
= 6 u - (3 u - 23)
= 6 u - 3 u + 23
= 3 u + 23
= 3 x 18 + 23
= 54 + 23
= 77
Answer(s): 77
