Michael had a total of 260 persimmons and kiwis. He sold
14 of the kiwis and bought another 40 persimmons. In the end, the number of persimmons he had was
34 the number of kiwis. How many more kiwis than persimmons did he have at first?
| |
Persimmons |
Kiwis |
Total |
Before
|
9 u - 40
|
4x4 =
16 u |
260 |
Change |
+ 40 |
- 1x4 =
4 u |
|
| After |
|
3x4 =
12 u |
|
Comparing between
persimmons and kiwis |
3x3 =
9 u |
4x3 =
12 u |
|
The number of kiwis in the end is repeated. Make the number of kiwis in the end the same. LCM of 3 and 4 is 12.
Total number of persimmons and kiwis at first
= 9 u - 40 + 16 u
= 25 u - 40
25 u - 40 = 260
25 u = 260 + 40
25 u = 300
1 u = 300 ÷ 25 = 12
Number of more kiwis than persimmons at first
= 16 u - (9 u - 40)
= 16 u - 9 u + 40
= 7 u + 40
= 7 x 12 + 40
= 84 + 40
= 124
Answer(s): 124
