Julian had a total of 536 lemons and persimmons. He sold
14 of the persimmons and bought another 39 lemons. In the end, the number of lemons he had was
34 the number of persimmons. How many more persimmons than lemons did he have at first?
| |
Lemons |
Persimmons |
Total |
Before
|
9 u - 39
|
4x4 =
16 u |
536 |
Change |
+ 39 |
- 1x4 =
4 u |
|
| After |
|
3x4 =
12 u |
|
Comparing between
lemons and persimmons |
3x3 =
9 u |
4x3 =
12 u |
|
The number of persimmons in the end is repeated. Make the number of persimmons in the end the same. LCM of 3 and 4 is 12.
Total number of lemons and persimmons at first
= 9 u - 39 + 16 u
= 25 u - 39
25 u - 39 = 536
25 u = 536 + 39
25 u = 575
1 u = 575 ÷ 25 = 23
Number of more persimmons than lemons at first
= 16 u - (9 u - 39)
= 16 u - 9 u + 39
= 7 u + 39
= 7 x 23 + 39
= 161 + 39
= 200
Answer(s): 200
