Henry had a total of 278 kiwis and pears. He sold
13 of the pears and bought another 34 kiwis. In the end, the number of kiwis he had was
23 the number of pears. How many more pears than kiwis did he have at first?
| |
Kiwis |
Pears |
Total |
Before
|
4 u - 34
|
3x3 =
9 u |
278 |
Change |
+ 34 |
- 1x3 =
3 u |
|
| After |
|
2x3 =
6 u |
|
Comparing between
kiwis and pears |
2x2 =
4 u |
3x2 =
6 u |
|
The number of pears in the end is repeated. Make the number of pears in the end the same. LCM of 2 and 3 is 6.
Total number of kiwis and pears at first
= 4 u - 34 + 9 u
= 13 u - 34
13 u - 34 = 278
13 u = 278 + 34
13 u = 312
1 u = 312 ÷ 13 = 24
Number of more pears than kiwis at first
= 9 u - (4 u - 34)
= 9 u - 4 u + 34
= 5 u + 34
= 5 x 24 + 34
= 120 + 34
= 154
Answer(s): 154
