Tommy had a total of 113 lemons and passion fruits. He sold
13 of the passion fruits and bought another 22 lemons. In the end, the number of lemons he had was
34 the number of passion fruits. How many more passion fruits than lemons did he have at first?
| |
Lemons |
Passion Fruits |
Total |
Before
|
3 u - 22
|
3x2 =
6 u |
113 |
Change |
+ 22 |
- 1x2 =
2 u |
|
| After |
|
2x2 =
4 u |
|
Comparing between
lemons and passion fruits |
3x1 =
3 u |
4x1 =
4 u |
|
The number of passion fruits in the end is repeated. Make the number of passion fruits in the end the same. LCM of 2 and 4 is 4.
Total number of lemons and passion fruits at first
= 3 u - 22 + 6 u
= 9 u - 22
9 u - 22 = 113
9 u = 113 + 22
9 u = 135
1 u = 135 ÷ 9 = 15
Number of more passion fruits than lemons at first
= 6 u - (3 u - 22)
= 6 u - 3 u + 22
= 3 u + 22
= 3 x 15 + 22
= 45 + 22
= 67
Answer(s): 67
