Zane had a total of 222 pomegranates and pears. He sold
34 of the pears and bought another 16 pomegranates. In the end, the number of pomegranates he had was
23 the number of pears. How many more pears than pomegranates did he have at first?
| |
Pomegranates |
Pears |
Total |
Before
|
2 u - 16
|
4x3 =
12 u |
222 |
Change |
+ 16 |
- 3x3 =
9 u |
|
| After |
|
1x3 =
3 u |
|
Comparing between
pomegranates and pears |
2x1 =
2 u |
3x1 =
3 u |
|
The number of pears in the end is repeated. Make the number of pears in the end the same. LCM of 1 and 3 is 3.
Total number of pomegranates and pears at first
= 2 u - 16 + 12 u
= 14 u - 16
14 u - 16 = 222
14 u = 222 + 16
14 u = 238
1 u = 238 ÷ 14 = 17
Number of more pears than pomegranates at first
= 12 u - (2 u - 16)
= 12 u - 2 u + 16
= 10 u + 16
= 10 x 17 + 16
= 170 + 16
= 186
Answer(s): 186
