Gabriel had a total of 320 pears and chikoos. He sold
34 of the chikoos and bought another 16 pears. In the end, the number of pears he had was
45 the number of chikoos. How many more chikoos than pears did he have at first?
| |
Pears |
Chikoos |
Total |
Before
|
4 u - 16
|
4x5 =
20 u |
320 |
Change |
+ 16 |
- 3x5 =
15 u |
|
| After |
|
1x5 =
5 u |
|
Comparing between
pears and chikoos |
4x1 =
4 u |
5x1 =
5 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 1 and 5 is 5.
Total number of pears and chikoos at first
= 4 u - 16 + 20 u
= 24 u - 16
24 u - 16 = 320
24 u = 320 + 16
24 u = 336
1 u = 336 ÷ 24 = 14
Number of more chikoos than pears at first
= 20 u - (4 u - 16)
= 20 u - 4 u + 16
= 16 u + 16
= 16 x 14 + 16
= 224 + 16
= 240
Answer(s): 240
