Rael had a total of 101 chikoos and mangoes. He sold
12 of the mangoes and bought another 20 chikoos. In the end, the number of chikoos he had was
15 the number of mangoes. How many more mangoes than chikoos did he have at first?
| |
Chikoos |
Mangoes |
Total |
Before
|
1 u - 20
|
2x5 =
10 u |
101 |
Change |
+ 20 |
- 1x5 =
5 u |
|
| After |
|
1x5 =
5 u |
|
Comparing between
chikoos and mangoes |
1x1 =
1 u |
5x1 =
5 u |
|
The number of mangoes in the end is repeated. Make the number of mangoes in the end the same. LCM of 1 and 5 is 5.
Total number of chikoos and mangoes at first
= 1 u - 20 + 10 u
= 11 u - 20
11 u - 20 = 101
11 u = 101 + 20
11 u = 121
1 u = 121 ÷ 11 = 11
Number of more mangoes than chikoos at first
= 10 u - (1 u - 20)
= 10 u - 1 u + 20
= 9 u + 20
= 9 x 11 + 20
= 99 + 20
= 119
Answer(s): 119
