Gabriel had a total of 477 passion fruits and chikoos. He sold
15 of the chikoos and bought another 29 passion fruits. In the end, the number of passion fruits he had was
23 the number of chikoos. How many more chikoos than passion fruits did he have at first?
| |
Passion Fruits |
Chikoos |
Total |
Before
|
8 u - 29
|
5x3 =
15 u |
477 |
Change |
+ 29 |
- 1x3 =
3 u |
|
| After |
|
4x3 =
12 u |
|
Comparing between
passion fruits and chikoos |
2x4 =
8 u |
3x4 =
12 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 4 and 3 is 12.
Total number of passion fruits and chikoos at first
= 8 u - 29 + 15 u
= 23 u - 29
23 u - 29 = 477
23 u = 477 + 29
23 u = 506
1 u = 506 ÷ 23 = 22
Number of more chikoos than passion fruits at first
= 15 u - (8 u - 29)
= 15 u - 8 u + 29
= 7 u + 29
= 7 x 22 + 29
= 154 + 29
= 183
Answer(s): 183
