Michael had a total of 269 persimmons and chikoos. He sold
34 of the chikoos and bought another 20 persimmons. In the end, the number of persimmons he had was
14 the number of chikoos. How many more chikoos than persimmons did he have at first?
| |
Persimmons |
Chikoos |
Total |
Before
|
1 u - 20
|
4x4 =
16 u |
269 |
Change |
+ 20 |
- 3x4 =
12 u |
|
| After |
|
1x4 =
4 u |
|
Comparing between
persimmons and chikoos |
1x1 =
1 u |
4x1 =
4 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 1 and 4 is 4.
Total number of persimmons and chikoos at first
= 1 u - 20 + 16 u
= 17 u - 20
17 u - 20 = 269
17 u = 269 + 20
17 u = 289
1 u = 289 ÷ 17 = 17
Number of more chikoos than persimmons at first
= 16 u - (1 u - 20)
= 16 u - 1 u + 20
= 15 u + 20
= 15 x 17 + 20
= 255 + 20
= 275
Answer(s): 275
