Tom had a total of 133 kiwis and passion fruits. He sold
12 of the passion fruits and bought another 21 kiwis. In the end, the number of kiwis he had was
13 the number of passion fruits. How many more passion fruits than kiwis did he have at first?
| |
Kiwis |
Passion Fruits |
Total |
Before
|
1 u - 21
|
2x3 =
6 u |
133 |
Change |
+ 21 |
- 1x3 =
3 u |
|
| After |
|
1x3 =
3 u |
|
Comparing between
kiwis and passion fruits |
1x1 =
1 u |
3x1 =
3 u |
|
The number of passion fruits in the end is repeated. Make the number of passion fruits in the end the same. LCM of 1 and 3 is 3.
Total number of kiwis and passion fruits at first
= 1 u - 21 + 6 u
= 7 u - 21
7 u - 21 = 133
7 u = 133 + 21
7 u = 154
1 u = 154 ÷ 7 = 22
Number of more passion fruits than kiwis at first
= 6 u - (1 u - 21)
= 6 u - 1 u + 21
= 5 u + 21
= 5 x 22 + 21
= 110 + 21
= 131
Answer(s): 131
