Pierre had a total of 313 mangoes and pomegranates. He sold
13 of the pomegranates and bought another 12 mangoes. In the end, the number of mangoes he had was
23 the number of pomegranates. How many more pomegranates than mangoes did he have at first?
| |
Mangoes |
Pomegranates |
Total |
Before
|
4 u - 12
|
3x3 =
9 u |
313 |
Change |
+ 12 |
- 1x3 =
3 u |
|
| After |
|
2x3 =
6 u |
|
Comparing between
mangoes and pomegranates |
2x2 =
4 u |
3x2 =
6 u |
|
The number of pomegranates in the end is repeated. Make the number of pomegranates in the end the same. LCM of 2 and 3 is 6.
Total number of mangoes and pomegranates at first
= 4 u - 12 + 9 u
= 13 u - 12
13 u - 12 = 313
13 u = 313 + 12
13 u = 325
1 u = 325 ÷ 13 = 25
Number of more pomegranates than mangoes at first
= 9 u - (4 u - 12)
= 9 u - 4 u + 12
= 5 u + 12
= 5 x 25 + 12
= 125 + 12
= 137
Answer(s): 137
