Pierre had a total of 708 starfruits and chikoos. He sold
15 of the chikoos and bought another 17 starfruits. In the end, the number of starfruits he had was
15 the number of chikoos. How many more chikoos than starfruits did he have at first?
|
Starfruits |
Chikoos |
Total |
Before
|
4 u - 17
|
5x5 = 25 u |
708 |
Change |
+ 17 |
- 1x5 = 5 u |
|
After |
|
4x5 = 20 u |
|
Comparing between starfruits and chikoos |
1x4 = 4 u |
5x4 = 20 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 4 and 5 is 20.
Total number of starfruits and chikoos at first
= 4 u - 17 + 25 u
= 29 u - 17
29 u - 17 = 708
29 u = 708 + 17
29 u = 725
1 u = 725 ÷ 29 = 25
Number of more chikoos than starfruits at first
= 25 u - (4 u - 17)
= 25 u - 4 u + 17
= 21 u + 17
= 21 x 25 + 17
= 525 + 17
= 542
Answer(s): 542