Ian had a total of 96 oranges and pears. He sold
13 of the pears and bought another 21 oranges. In the end, the number of oranges he had was
34 the number of pears. How many more pears than oranges did he have at first?
| |
Oranges |
Pears |
Total |
Before
|
3 u - 21
|
3x2 =
6 u |
96 |
Change |
+ 21 |
- 1x2 =
2 u |
|
| After |
|
2x2 =
4 u |
|
Comparing between
oranges and pears |
3x1 =
3 u |
4x1 =
4 u |
|
The number of pears in the end is repeated. Make the number of pears in the end the same. LCM of 2 and 4 is 4.
Total number of oranges and pears at first
= 3 u - 21 + 6 u
= 9 u - 21
9 u - 21 = 96
9 u = 96 + 21
9 u = 117
1 u = 117 ÷ 9 = 13
Number of more pears than oranges at first
= 6 u - (3 u - 21)
= 6 u - 3 u + 21
= 3 u + 21
= 3 x 13 + 21
= 39 + 21
= 60
Answer(s): 60
