Sean had a total of 157 pears and kiwis. He sold
34 of the kiwis and bought another 38 pears. In the end, the number of pears he had was
13 the number of kiwis. How many more kiwis than pears did he have at first?
| |
Pears |
Kiwis |
Total |
Before
|
1 u - 38
|
4x3 =
12 u |
157 |
Change |
+ 38 |
- 3x3 =
9 u |
|
| After |
|
1x3 =
3 u |
|
Comparing between
pears and kiwis |
1x1 =
1 u |
3x1 =
3 u |
|
The number of kiwis in the end is repeated. Make the number of kiwis in the end the same. LCM of 1 and 3 is 3.
Total number of pears and kiwis at first
= 1 u - 38 + 12 u
= 13 u - 38
13 u - 38 = 157
13 u = 157 + 38
13 u = 195
1 u = 195 ÷ 13 = 15
Number of more kiwis than pears at first
= 12 u - (1 u - 38)
= 12 u - 1 u + 38
= 11 u + 38
= 11 x 15 + 38
= 165 + 38
= 203
Answer(s): 203
