Tom had a total of 655 persimmons and pears. He sold
15 of the pears and bought another 38 persimmons. In the end, the number of persimmons he had was
25 the number of pears. How many more pears than persimmons did he have at first?
| |
Persimmons |
Pears |
Total |
Before
|
8 u - 38
|
5x5 =
25 u |
655 |
Change |
+ 38 |
- 1x5 =
5 u |
|
| After |
|
4x5 =
20 u |
|
Comparing between
persimmons and pears |
2x4 =
8 u |
5x4 =
20 u |
|
The number of pears in the end is repeated. Make the number of pears in the end the same. LCM of 4 and 5 is 20.
Total number of persimmons and pears at first
= 8 u - 38 + 25 u
= 33 u - 38
33 u - 38 = 655
33 u = 655 + 38
33 u = 693
1 u = 693 ÷ 33 = 21
Number of more pears than persimmons at first
= 25 u - (8 u - 38)
= 25 u - 8 u + 38
= 17 u + 38
= 17 x 21 + 38
= 357 + 38
= 395
Answer(s): 395
