Seth had a total of 210 oranges and mangosteens. He sold
13 of the mangosteens and bought another 24 oranges. In the end, the number of oranges he had was
34 the number of mangosteens. How many more mangosteens than oranges did he have at first?
|
Oranges |
Mangosteens |
Total |
Before
|
3 u - 24
|
3x2 = 6 u |
210 |
Change |
+ 24 |
- 1x2 = 2 u |
|
After |
|
2x2 = 4 u |
|
Comparing between oranges and mangosteens |
3x1 = 3 u |
4x1 = 4 u |
|
The number of mangosteens in the end is repeated. Make the number of mangosteens in the end the same. LCM of 2 and 4 is 4.
Total number of oranges and mangosteens at first
= 3 u - 24 + 6 u
= 9 u - 24
9 u - 24 = 210
9 u = 210 + 24
9 u = 234
1 u = 234 ÷ 9 = 26
Number of more mangosteens than oranges at first
= 6 u - (3 u - 24)
= 6 u - 3 u + 24
= 3 u + 24
= 3 x 26 + 24
= 78 + 24
= 102
Answer(s): 102