Ahmad had a total of 146 apples and oranges. He sold
12 of the oranges and bought another 22 apples. In the end, the number of apples he had was
13 the number of oranges. How many more oranges than apples did he have at first?
| |
Apples |
Oranges |
Total |
Before
|
1 u - 22
|
2x3 =
6 u |
146 |
Change |
+ 22 |
- 1x3 =
3 u |
|
| After |
|
1x3 =
3 u |
|
Comparing between
apples and oranges |
1x1 =
1 u |
3x1 =
3 u |
|
The number of oranges in the end is repeated. Make the number of oranges in the end the same. LCM of 1 and 3 is 3.
Total number of apples and oranges at first
= 1 u - 22 + 6 u
= 7 u - 22
7 u - 22 = 146
7 u = 146 + 22
7 u = 168
1 u = 168 ÷ 7 = 24
Number of more oranges than apples at first
= 6 u - (1 u - 22)
= 6 u - 1 u + 22
= 5 u + 22
= 5 x 24 + 22
= 120 + 22
= 142
Answer(s): 142
