Ian had a total of 532 chikoos and pears. He sold
25 of the pears and bought another 19 chikoos. In the end, the number of chikoos he had was
34 the number of pears. How many more pears than chikoos did he have at first?
| |
Chikoos |
Pears |
Total |
Before
|
9 u - 19
|
5x4 =
20 u |
532 |
Change |
+ 19 |
- 2x4 =
8 u |
|
| After |
|
3x4 =
12 u |
|
Comparing between
chikoos and pears |
3x3 =
9 u |
4x3 =
12 u |
|
The number of pears in the end is repeated. Make the number of pears in the end the same. LCM of 3 and 4 is 12.
Total number of chikoos and pears at first
= 9 u - 19 + 20 u
= 29 u - 19
29 u - 19 = 532
29 u = 532 + 19
29 u = 551
1 u = 551 ÷ 29 = 19
Number of more pears than chikoos at first
= 20 u - (9 u - 19)
= 20 u - 9 u + 19
= 11 u + 19
= 11 x 19 + 19
= 209 + 19
= 228
Answer(s): 228
