Luke and Cole had $720 altogether. Cole gave
25 of his money to Luke. After that, Luke gave
35 of his money to Cole. In the end, Luke had
15 of the total sum of money. How much did Luke have at first?
| |
Cole |
Luke |
Total |
| Before 1 |
5 p |
? |
$720 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$720 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$720 |
Comparing between
Cole and Luke
in the end |
4x2 =
8 u |
1x2 =
2 u |
$720 |
The amount that Luke had in the end is the repeated. Make the amount that Luke had in the end the same. LCM of 2 and 1 is 2.
10 u = 720
1 u = 720 ÷ 10 = 72
5 u = 5 x 72 = 360
3 p = 720 - 360 = 360
1 p = 360 ÷ 3 = 120
Amount that Cole had at first
= 5 p
= 5 x 120
= $600
Amount that Luke had at first
= 720 - 600
= $120
Answer(s): $120
