Gabriel and Ken had $1044 altogether. Ken gave
25 of his money to Gabriel. After that, Gabriel gave
35 of his money to Ken. In the end, Gabriel had
16 of the total sum of money. How much did Gabriel have at first?
| |
Ken |
Gabriel |
Total |
| Before 1 |
5 p |
? |
$1044 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$1044 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$1044 |
Comparing between
Ken and Gabriel
in the end |
5x2 =
10 u |
1x2 =
2 u |
$1044 |
The amount that Gabriel had in the end is the repeated. Make the amount that Gabriel had in the end the same. LCM of 2 and 1 is 2.
12 u = 1044
1 u = 1044 ÷ 12 = 87
5 u = 5 x 87 = 435
3 p = 1044 - 435 = 609
1 p = 609 ÷ 3 = 203
Amount that Ken had at first
= 5 p
= 5 x 203
= $1015
Amount that Gabriel had at first
= 1044 - 1015
= $29
Answer(s): $29
