Simon and Seth had $540 altogether. Seth gave
25 of his money to Simon. After that, Simon gave
35 of his money to Seth. In the end, Simon had
15 of the total sum of money. How much did Simon have at first?
| |
Seth |
Simon |
Total |
| Before 1 |
5 p |
? |
$540 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$540 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$540 |
Comparing between
Seth and Simon
in the end |
4x2 =
8 u |
1x2 =
2 u |
$540 |
The amount that Simon had in the end is the repeated. Make the amount that Simon had in the end the same. LCM of 2 and 1 is 2.
10 u = 540
1 u = 540 ÷ 10 = 54
5 u = 5 x 54 = 270
3 p = 540 - 270 = 270
1 p = 270 ÷ 3 = 90
Amount that Seth had at first
= 5 p
= 5 x 90
= $450
Amount that Simon had at first
= 540 - 450
= $90
Answer(s): $90
