Rael and Neave had $540 altogether. Neave gave
25 of his money to Rael. After that, Rael gave
35 of his money to Neave. In the end, Rael had
15 of the total sum of money. How much did Rael have at first?
| |
Neave |
Rael |
Total |
| Before 1 |
5 p |
? |
$540 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$540 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$540 |
Comparing between
Neave and Rael
in the end |
4x2 =
8 u |
1x2 =
2 u |
$540 |
The amount that Rael had in the end is the repeated. Make the amount that Rael had in the end the same. LCM of 2 and 1 is 2.
10 u = 540
1 u = 540 ÷ 10 = 54
5 u = 5 x 54 = 270
3 p = 540 - 270 = 270
1 p = 270 ÷ 3 = 90
Amount that Neave had at first
= 5 p
= 5 x 90
= $450
Amount that Rael had at first
= 540 - 450
= $90
Answer(s): $90
