Ahmad and Jenson had $630 altogether. Jenson gave
25 of his money to Ahmad. After that, Ahmad gave
35 of his money to Jenson. In the end, Ahmad had
15 of the total sum of money. How much did Ahmad have at first?
| |
Jenson |
Ahmad |
Total |
| Before 1 |
5 p |
? |
$630 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$630 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$630 |
Comparing between
Jenson and Ahmad
in the end |
4x2 =
8 u |
1x2 =
2 u |
$630 |
The amount that Ahmad had in the end is the repeated. Make the amount that Ahmad had in the end the same. LCM of 2 and 1 is 2.
10 u = 630
1 u = 630 ÷ 10 = 63
5 u = 5 x 63 = 315
3 p = 630 - 315 = 315
1 p = 315 ÷ 3 = 105
Amount that Jenson had at first
= 5 p
= 5 x 105
= $525
Amount that Ahmad had at first
= 630 - 525
= $105
Answer(s): $105
