Rael and Cody had $144 altogether. Cody gave
25 of his money to Rael. After that, Rael gave
35 of his money to Cody. In the end, Rael had
16 of the total sum of money. How much did Rael have at first?
| |
Cody |
Rael |
Total |
| Before 1 |
5 p |
? |
$144 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$144 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$144 |
Comparing between
Cody and Rael
in the end |
5x2 =
10 u |
1x2 =
2 u |
$144 |
The amount that Rael had in the end is the repeated. Make the amount that Rael had in the end the same. LCM of 2 and 1 is 2.
12 u = 144
1 u = 144 ÷ 12 = 12
5 u = 5 x 12 = 60
3 p = 144 - 60 = 84
1 p = 84 ÷ 3 = 28
Amount that Cody had at first
= 5 p
= 5 x 28
= $140
Amount that Rael had at first
= 144 - 140
= $4
Answer(s): $4
