Asher and Cole had $756 altogether. Cole gave
25 of his money to Asher. After that, Asher gave
35 of his money to Cole. In the end, Asher had
16 of the total sum of money. How much did Asher have at first?
| |
Cole |
Asher |
Total |
| Before 1 |
5 p |
? |
$756 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$756 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$756 |
Comparing between
Cole and Asher
in the end |
5x2 =
10 u |
1x2 =
2 u |
$756 |
The amount that Asher had in the end is the repeated. Make the amount that Asher had in the end the same. LCM of 2 and 1 is 2.
12 u = 756
1 u = 756 ÷ 12 = 63
5 u = 5 x 63 = 315
3 p = 756 - 315 = 441
1 p = 441 ÷ 3 = 147
Amount that Cole had at first
= 5 p
= 5 x 147
= $735
Amount that Asher had at first
= 756 - 735
= $21
Answer(s): $21
