David and Lee had $612 altogether. Lee gave
25 of his money to David. After that, David gave
35 of his money to Lee. In the end, David had
16 of the total sum of money. How much did David have at first?
| |
Lee |
David |
Total |
| Before 1 |
5 p |
? |
$612 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$612 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$612 |
Comparing between
Lee and David
in the end |
5x2 =
10 u |
1x2 =
2 u |
$612 |
The amount that David had in the end is the repeated. Make the amount that David had in the end the same. LCM of 2 and 1 is 2.
12 u = 612
1 u = 612 ÷ 12 = 51
5 u = 5 x 51 = 255
3 p = 612 - 255 = 357
1 p = 357 ÷ 3 = 119
Amount that Lee had at first
= 5 p
= 5 x 119
= $595
Amount that David had at first
= 612 - 595
= $17
Answer(s): $17
