Liam and Luis had $72 altogether. Luis gave
25 of his money to Liam. After that, Liam gave
35 of his money to Luis. In the end, Liam had
16 of the total sum of money. How much did Liam have at first?
| |
Luis |
Liam |
Total |
| Before 1 |
5 p |
? |
$72 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$72 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$72 |
Comparing between
Luis and Liam
in the end |
5x2 =
10 u |
1x2 =
2 u |
$72 |
The amount that Liam had in the end is the repeated. Make the amount that Liam had in the end the same. LCM of 2 and 1 is 2.
12 u = 72
1 u = 72 ÷ 12 = 6
5 u = 5 x 6 = 30
3 p = 72 - 30 = 42
1 p = 42 ÷ 3 = 14
Amount that Luis had at first
= 5 p
= 5 x 14
= $70
Amount that Liam had at first
= 72 - 70
= $2
Answer(s): $2
