Neave and Sean had $540 altogether. Sean gave
25 of his money to Neave. After that, Neave gave
35 of his money to Sean. In the end, Neave had
15 of the total sum of money. How much did Neave have at first?
| |
Sean |
Neave |
Total |
| Before 1 |
5 p |
? |
$540 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$540 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$540 |
Comparing between
Sean and Neave
in the end |
4x2 =
8 u |
1x2 =
2 u |
$540 |
The amount that Neave had in the end is the repeated. Make the amount that Neave had in the end the same. LCM of 2 and 1 is 2.
10 u = 540
1 u = 540 ÷ 10 = 54
5 u = 5 x 54 = 270
3 p = 540 - 270 = 270
1 p = 270 ÷ 3 = 90
Amount that Sean had at first
= 5 p
= 5 x 90
= $450
Amount that Neave had at first
= 540 - 450
= $90
Answer(s): $90
