Ken and Bobby had $648 altogether. Bobby gave
25 of his money to Ken. After that, Ken gave
35 of his money to Bobby. In the end, Ken had
16 of the total sum of money. How much did Ken have at first?
| |
Bobby |
Ken |
Total |
| Before 1 |
5 p |
? |
$648 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$648 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$648 |
Comparing between
Bobby and Ken
in the end |
5x2 =
10 u |
1x2 =
2 u |
$648 |
The amount that Ken had in the end is the repeated. Make the amount that Ken had in the end the same. LCM of 2 and 1 is 2.
12 u = 648
1 u = 648 ÷ 12 = 54
5 u = 5 x 54 = 270
3 p = 648 - 270 = 378
1 p = 378 ÷ 3 = 126
Amount that Bobby had at first
= 5 p
= 5 x 126
= $630
Amount that Ken had at first
= 648 - 630
= $18
Answer(s): $18
