Gabriel and Peter had $810 altogether. Peter gave
25 of his money to Gabriel. After that, Gabriel gave
35 of his money to Peter. In the end, Gabriel had
15 of the total sum of money. How much did Gabriel have at first?
| |
Peter |
Gabriel |
Total |
| Before 1 |
5 p |
? |
$810 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$810 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$810 |
Comparing between
Peter and Gabriel
in the end |
4x2 =
8 u |
1x2 =
2 u |
$810 |
The amount that Gabriel had in the end is the repeated. Make the amount that Gabriel had in the end the same. LCM of 2 and 1 is 2.
10 u = 810
1 u = 810 ÷ 10 = 81
5 u = 5 x 81 = 405
3 p = 810 - 405 = 405
1 p = 405 ÷ 3 = 135
Amount that Peter had at first
= 5 p
= 5 x 135
= $675
Amount that Gabriel had at first
= 810 - 675
= $135
Answer(s): $135
