Pierre and Asher had $432 altogether. Asher gave
25 of his money to Pierre. After that, Pierre gave
35 of his money to Asher. In the end, Pierre had
16 of the total sum of money. How much did Pierre have at first?
| |
Asher |
Pierre |
Total |
| Before 1 |
5 p |
? |
$432 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$432 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$432 |
Comparing between
Asher and Pierre
in the end |
5x2 =
10 u |
1x2 =
2 u |
$432 |
The amount that Pierre had in the end is the repeated. Make the amount that Pierre had in the end the same. LCM of 2 and 1 is 2.
12 u = 432
1 u = 432 ÷ 12 = 36
5 u = 5 x 36 = 180
3 p = 432 - 180 = 252
1 p = 252 ÷ 3 = 84
Amount that Asher had at first
= 5 p
= 5 x 84
= $420
Amount that Pierre had at first
= 432 - 420
= $12
Answer(s): $12
