Ian and Ivan had $756 altogether. Ivan gave
25 of his money to Ian. After that, Ian gave
35 of his money to Ivan. In the end, Ian had
16 of the total sum of money. How much did Ian have at first?
| |
Ivan |
Ian |
Total |
| Before 1 |
5 p |
? |
$756 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$756 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$756 |
Comparing between
Ivan and Ian
in the end |
5x2 =
10 u |
1x2 =
2 u |
$756 |
The amount that Ian had in the end is the repeated. Make the amount that Ian had in the end the same. LCM of 2 and 1 is 2.
12 u = 756
1 u = 756 ÷ 12 = 63
5 u = 5 x 63 = 315
3 p = 756 - 315 = 441
1 p = 441 ÷ 3 = 147
Amount that Ivan had at first
= 5 p
= 5 x 147
= $735
Amount that Ian had at first
= 756 - 735
= $21
Answer(s): $21
