Ian and Howard had $90 altogether. Howard gave
25 of his money to Ian. After that, Ian gave
35 of his money to Howard. In the end, Ian had
15 of the total sum of money. How much did Ian have at first?
|
Howard |
Ian |
Total |
Before 1 |
5 p |
? |
$90 |
Change 1 |
- 2 p |
+ 2 p |
|
After 1 |
3 p |
5 u |
|
Before 2 |
3 p |
5x1 = 5 u |
$90 |
Change 2 |
+ 3x1 = + 3 u |
- 3x1 = - 3 u |
|
After 2 |
|
2x1 = 2 u |
$90 |
Comparing between Howard and Ian in the end |
4x2 = 8 u |
1x2 = 2 u |
$90 |
The amount that Ian had in the end is the repeated. Make the amount that Ian had in the end the same. LCM of 2 and 1 is 2.
10 u = 90
1 u = 90 ÷ 10 = 9
5 u = 5 x 9 = 45
3 p = 90 - 45 = 45
1 p = 45 ÷ 3 = 15
Amount that Howard had at first
= 5 p
= 5 x 15
= $75
Amount that Ian had at first
= 90 - 75
= $15
Answer(s): $15